Multiply these:
(i) (2x+5y) (3x-4y)
(ii) (2x+3) (2x-4)
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Answer:
1. (2x+5y)(3x-4y)
=2x(3x-4y) + 5y(3x-4y)
= 6x²-8xy+15xy-20y²
= 6x²+7xy-20y²
2. (2x+3)(2x-4)
Using identity (x+a) (x+b) =x²+(a+b)x+ab
Here a=3, b=(-4) Now putting the values in the identity
=(2x+3)(2x-4)=(2x)²+[3+(-4)]2x+3×(-4)
=4x²-5x-12
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