Question

multiply using appropriate identies (3x+1) (3x-8)
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Answer 1

Answer:

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$(3x - 1)(3x - 8) \\ 3x(3x - 8) - 1(3x - 8) \\ {9}x^{2} - 24x - 3x + 8 \\ 9 {x}^{2} - 27x + 8 \: is \: your \: answer$

❤️hope it's help you❤️✅

Answer 2

$\huge{\orange{\underline{\underline{\bf{SoluTion:}}}}}$

Given,

(3x+1)(3x-8)

By Using Identity

$\boxed{\bf{(a+b)(a-b) = a²-a(b-c)-bc}}$

$→\;{\tt{(3x)²-3x(1+8)+8}}$

$→\;{\sf{9x²-27x+8 = 0}}$

By Factorisation

$→\;{\tt{9x²-24x+3x+8 = 0}}$

$→\;{\tt{3x(3x-8)+1(3x+8) = 0}}$

$→\;{\tt{(3x-8)(3x+1) = 0}}$

➝ $\fbox\red{\sf{3x = 8 or -1}}$

Hope It Helps You ✌️