Multiply using appropriate identities (3x+1) (3x-8)
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Answered by
26
Answer:
Step-by-step explanation:
3x+1/3x=8
Cubing both sides
(3x+1/3x)^3=(8)^3
27x3+1/27x3+3(3x)(1/3x)(3x+1/3x)=512 ...(using the identity:(a+b)^3)
27x3+1/27x3+3(8)=512 ...(3x*1/3x=1, 3x+1/3x=8)
27x3+1/27x3+24=512
27x3+1/27x3=512-24
27x3+1/27x3=488
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15
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