Math, asked by 1978dassukumar, 4 days ago

Multiply with 123×567ans =? now say me ans with 176 add​

Answers

Answered by Itzintellectual
14

Step-by-step explanation:

123 \times 567 \\  \\  = 69741

Given:

The sum of two digits number and the number obtained by reversing the order of its digit = 143

Difference of digits = 3

Calculation:

Let the original number be xy = 10x + y

x – y = 3

⇒ x = 3 + y

Reversed number obtained by reversing digits of original number = yx = 10y + x

10x + y + 10y + x = 143

⇒ 10 (3 + y) + y + 10y + 3 + y = 143

⇒ 30 + 10y + y + 10y + 3 + y = 143

⇒ 22y = 143 – 33

⇒ 22y = 110

⇒ y = 110/22

⇒ y = 5

y = 5 then x = 3 + 5 = 8

∴Then the original number is 85

Answered by Itzintellectual
1

Step-by-step explanation:

123 \times 567 \\  \\  = 69741

Given:

The sum of two digits number and the number obtained by reversing the order of its digit = 143

Difference of digits = 3

Calculation:

Let the original number be xy = 10x + y

x – y = 3

⇒ x = 3 + y

Reversed number obtained by reversing digits of original number = yx = 10y + x

10x + y + 10y + x = 143

⇒ 10 (3 + y) + y + 10y + 3 + y = 143

⇒ 30 + 10y + y + 10y + 3 + y = 143

⇒ 22y = 143 – 33

⇒ 22y = 110

⇒ y = 110/22

⇒ y = 5

y = 5 then x = 3 + 5 = 8

∴Then the original number is 85

Answered by Itzintellectual
2

Step-by-step explanation:

123 \times 567 \\  \\  = 69741

Given:

The sum of two digits number and the number obtained by reversing the order of its digit = 143

Difference of digits = 3

Calculation:

Let the original number be xy = 10x + y

x – y = 3

⇒ x = 3 + y

Reversed number obtained by reversing digits of original number = yx = 10y + x

10x + y + 10y + x = 143

⇒ 10 (3 + y) + y + 10y + 3 + y = 143

⇒ 30 + 10y + y + 10y + 3 + y = 143

⇒ 22y = 143 – 33

⇒ 22y = 110

⇒ y = 110/22

⇒ y = 5

y = 5 then x = 3 + 5 = 8

∴Then the original number is 85

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