Question

Multiply: (x^3 – 2x 2 + 3x – 4) (x – 1) – (2x – 3) (x^2 – x + 1)

Answer 1

Answer:

CBSE

CBSE Class 8

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Answer in Brief

Simplify:

(x3 − 2x2 + 3x − 4) (x −1) − (2x − 3)(x2 − x + 1)

SOLUTION

To simplify,we will proceed as follows:

(x3−2x2+3x−4)(x−1)−(2x−3)(x2−x+1)

=[(x3−2x2+3x−4)(x−1)]−[(2x−3)(x2−x+1)]

=[x(x3−2x2+3x−4)−1(x3−2x2+3x−4)]−[2x(x2−x+1)−3(x2−x+1)]

(Distributive law)

=[x(x3−2x2+3x−4)−1(x3−2x2+3x−4)]−[2x(x2−x+1)−3(x2−x+1)]

=x4−2x3+3x2−4x−x3+2x2−3x+4−[2x3−2x2+2x−3x2+3x−3]

=x4−2x3+3x2−4x−x3+2x2−3x+4−2x3+2x2−2x+3x2−3x+3

=x4−2x3−2x3−x3+3x2+2x2+2x2+3x2−4x−3x−2x−3x+4+3

(Rearranging)

=x4−5x3+10x2−12x+7

(Combining like terms)

Thus, the answer is

x4−5x3+10x2−12x+7

.

Answer 2

Answer:

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