Question

Multiply (x+4) by ( x²-4x+16)​

Answer 1

$\huge\bold\red{Given:-}$

Velocity of a car started from rest reaches 24 m/s in 4s

$\huge\bold\pink{To~find:-}$

$\sf{Initial ~velocity}$

$\sf{Final ~velocity}$

$\sf{Acceleration}$

$\huge\bold\purple{SolutiØn:-}$

$\sf{Initial~velocity=0~{started~from~rest}}$

$\sf{Final~velocity=24~m/s}$

$\sf{Time=4s}$

$\bold\orange{According~to~the~first~equation ~of ~the~motion:-}$

$\longrightarrow$$\sf\green{v=u+at}$

Where “v” is final velocity “u” is initial velocity, “a” is acceleration and “t” is time taken.

$\huge\bold\pink{Put~the~values:-}$

$\longrightarrow$ $\sf{24=0+a×4}$

$\longrightarrow$ $\sf{a=}$$\frac{24}{4}$

$\longrightarrow$ $\sf{a=6~m/s²}$

$\huge\mathfrak\purple{Hence,}$

Acceleration of the car is 6 m/s²

$\huge{\underline{\texttt{\pink{More~to~know→}}}}$

$\sf{s=ut+at²(second~equation~of~motion)}$

$\sf{v²=u²+2as(Third~equation~of~motion)}$

Negative value of acceleration is known as retardation.

Answer 2

Answer:

Same as my frnd kotangesh