Multiply: (x-a)(x-b)(x-c)...(x-z)
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Actually this question I am getting since long back. With a little bit zooming we see prior to (x-z) there is (x-y ) and just before (x-y) there is (x -x) which is equal to 0 and hence product of entire sequence will be zero (0). So the value of (x-a)(x-b)(x-c)…..(x-z) is 0.
soumamax:
thank you
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Step-by-step explanation:
x+a x+b x+c x+d and etcetera
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