Math, asked by soumamax, 1 year ago

Multiply: (x-a)(x-b)(x-c)...(x-z)​

Answers

Answered by ananyamohanty2005
1

Answer:

Actually this question I am getting since long back. With a little bit zooming we see prior to (x-z) there is (x-y ) and just before (x-y) there is (x -x) which is equal to 0 and hence product of entire sequence will be zero (0). So the value of (x-a)(x-b)(x-c)…..(x-z) is 0.


soumamax: thank you
ananyamohanty2005: pleasure is all mine...
soumamax: who are you?
Answered by anjalaia306
0

Answer:

0

Step-by-step explanation:

x+a x+b x+c x+d and etcetera

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