Question

multiply (z+1/6)(z-6) using identity​

Answer 1

Answer:

There are 6 possible values for v that you get from the equation v6=1. But to go from a value of v to a value of z which solves the original equation, you have to solve v=zz−1 for z, and when v=1 there is no such solution. For if v=1, then we would have to have 1=zz−1, or z=z−1, and this is impossible.