multiplying (a+bc) and (ab-c) the answers is
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Step-by-step explanation:
Answer
(ab+bc+ca)(ab−bc−ca)
=[ab+(bc+ca)][ab−(bc+ca)]
=(ab)
2
−(bc+ca)
2
=a
2
b
2
−(b
2
c
2
+c
2
a
2
+2abc
2
)
=a
2
b
2
−b
2
c
2
−c
2
a
2
−2abc
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