Math, asked by shreyanshhh, 11 months ago

Murali sells samosas for a living. He sells each samosa for rs4 and works from Monday to Saturday every week. He observes that he sells X samosas less than the previous day on 2 days of any week and X samosas more than the previous day on the other three days of the week. Every week, the highest number of samosas that he sells on any day is 150 and the least number of samosas he sells is 90.​

Answers

Answered by ab2929
0

Answer: 240

Step-by-step explanation:

4+150=154

154+90=240

240 is the correct answer.

Answered by bonumahanthic
0

Answer:

Therefore, Murali's total revenue for the week is between rs860 and rs2100.

Step-by-step explanation:

Let's assume that Murali sells N samosas on Monday. According to the problem, he sells X samosas less than the previous day on 2 days of the week and X samosas more than the previous day on the other 3 days of the week. Let's assume that he sells N-X samosas on Tuesday and Wednesday, and N+X samosas on Thursday, Friday, and Saturday.

Given that the highest number of samosas he sells on any day is 150 and the least number of samosas he sells is 90, we can write the following inequalities:

N+X ≤ 150

N-X ≥ 90

N-X ≤ 150

N+X ≥ 90

Solving these inequalities, we get:

N ≤ 105-X/2

N ≥ X/2+75

Since Murali sells an integer number of samosas, we can round the upper and lower bounds to the nearest integer. Therefore, we get:

N ≤ 105-X/2 ≈ 105-X/2 (rounded down to nearest integer)

N ≥ X/2+75 ≈ X/2+75 (rounded up to nearest integer)

Now, let's consider the total revenue that Murali earns in a week. If he sells N samosas on Monday, then he sells N-X, N-X, N+X, N+X, and N+X samosas on Tuesday to Saturday, respectively. Therefore, his total revenue for the week can be calculated as:

Revenue = 4N + 4(N-X) + 4(N-X) + 4(N+X) + 4(N+X) + 4(N+X)

Revenue = 20N + 8X

Substituting the upper bound of N and lower bound of X, we get:

Revenue ≤ 20(105-X/2) + 8X

Revenue ≥ 20(X/2+75) + 8X

Simplifying, we get:

Revenue ≤ 2100 - 6X

Revenue ≥ 860 + 28X

Therefore, Murali's total revenue for the week is between rs860 and rs2100.

To know more about total revenue for the week refer :

https://brainly.in/question/13832666

https://brainly.in/question/5451074

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