Math, asked by Prosnipzz, 3 months ago

murali sold 2 articles with Rs6210 in one them hain is 8%and another 8% loss dind overall gain or loss​

Answers

Answered by itzkriti279
0

Answer:

The nucleoid (meaning nucleus-like) is an irregularly shaped region within the prokaryotic cell that contains all or most of the genetic material.[1][2][3] The chromosome of a prokaryote is circular, and its length is very large compared to the cell dimensions needing it to be compacted in order to fit. In contrast to the nucleus of a eukaryotic cell, it is not surrounded by a nuclear membrane. Instead, the nucleoid forms by condensation and functional arrangement with the help of chromosomal architectural proteins and RNA molecules as well as DNA supercoiling. The length of a genome widely varies (generally at least a few million base pairs) and a cell may contain multiple copies of it.

Answered by MasterDhruva
30

Correct Question :-

Murali sold two articles for ₹6210 each. In one of them he gained 8% and in the other he lost 8%. Find his overall gain or loss percentage.

\:

Given :-

Selling price of each article :- ₹6210

Gain percentage of first :- 8%

Loss percentage of second :- 8%

\:

To Find :-

Overall gain or loss percentage obtained by Murali.

\:

Formula required :-

{\large \dashrightarrow \orange{\boxed{\tt \gray{\dfrac{Profit \: (or) \: Loss}{CP} \times 100}}}}

\:

How to do :-

Here, we are given that a boy sells two articles at a same price. He gains some percentage on the first article and some of the loss percentage on the second article. We are asked to find the overall gain or loss percentage on the whole transition. So, first we should find the cost price of both the articles separately by using the formula given below. Then, we should add both the cost price. Next, we should add both the selling price together. Now, we should find the loss rupees by subtracting the cost price and the selling price. Later, we can use the given formula for calculating the loss percentage.

\:

Solution :-

Cost price of first article :-

{\tt \leadsto \dfrac{100}{(100 + 8)} \times 6210}

{\tt \leadsto \cancel \dfrac{100}{108} \times 6210 = \dfrac{25}{27} \times 6210}

{\tt \leadsto \dfrac{25}{\cancel{27}} \times \cancel{6210} = \dfrac{25}{1} \times 230}

{\tt \leadsto \dfrac{25 \times 230}{1} = \dfrac{5750}{1}}

\:

Cost price of second article :-

{\tt \leadsto \dfrac{100}{(100 - 8)} \times 6210}

{\tt \leadsto \dfrac{100}{ \cancel{92}} \times \cancel{6210} = \dfrac{100}{46} \times 3105}

{\tt \leadsto \cancel \dfrac{100}{46} \times 3105 = \dfrac{50}{23} \times 3105}

{\tt \leadsto \dfrac{50}{\cancel{23}} \times \cancel{3105} = \dfrac{50 \times 135}{1}}

{\tt \leadsto \cancel \dfrac{6750}{1} = 6750}

\:

Total cost price :-

{\tt \leadsto 5750 + 6750}

{\tt \leadsto Rs \: \: 12500}

Total selling price :-

{\tt \leadsto 6210 + 6210}

{\tt \leadsto Rs \: \: 12420}

\:

Loss rupees :-

{\tt \leadsto 12500 - 12420}

{\tt \leadsto Rs \: \: 80}

\:

Now,

Loss percentage :-

{\tt \leadsto \dfrac{80}{12500} \times 100}

{\tt \leadsto \dfrac{80}{\cancel{12500}} \times \cancel{100} = \dfrac{80}{125}}

{\tt \leadsto \cancel \dfrac{80}{125} = \boxed{ \tt 0.64 \bf\%}}

\Huge\therefore The loss percentage obtained on whole transaction is 0.64%.

━━━━━━━━━━━━━━━━━━━━━━

\small\boxed{  \begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\   \bigstar \:  \sf{Gain = S.P – C.P} \\ \\ \bigstar \:\sf{Loss = C.P – S.P} \\  \\ \bigstar \:  \sf{S.P = \dfrac{100+Gain\%}{100} \times C.P} \\  \\ \bigstar \:  \sf{  C.P =\dfrac{100}{100+Gain\%} \times S.P}  \\  \\\bigstar \:  \sf{  S.P =  \dfrac{100-loss\%}{100} \times C.P}  \\  \\ \bigstar \:  \sf{  C.P =\dfrac{100}{100-loss\%} \times S.P}\end{array}}

Similar questions