Murari has total of rs 210 in one rupee 50 paise and 25 paisa coins . they were in the ratio 2.5 : 3 : 4 . how many one rupee coins were there
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Let the number of 1 rupee coins, 50 paise coins and 25 paise coins be 2.5x, 3x, and 4x resp.
So, we have
100(2.5x) + 50(3x) + 25(4x) = 210 x 100 paise
This is the total money Murari has with him
So,
250x + 150x + 100x = 21000
500x = 21000
x = 21000/500
x = 42
Thus, no. of coins of 1 rupee will be 2.5x
or 2.5(42) = 105 coins
So, we have
100(2.5x) + 50(3x) + 25(4x) = 210 x 100 paise
This is the total money Murari has with him
So,
250x + 150x + 100x = 21000
500x = 21000
x = 21000/500
x = 42
Thus, no. of coins of 1 rupee will be 2.5x
or 2.5(42) = 105 coins
Answered by
4
Solution:-
given by:-
》Murari has total of rs= 210
》coins type = one rupee , 50paise , 25 paise
》their ratio is = 2.5:3:4
》thirt coins = 2.5x , 3x ,4x
acourding to quetions-
change in paise
》2.5x×(100)+3x×(50)+4x×(25) = 210×100
》250x +150x+100x = 21000
》500x = 21000
》x= 21000/500
》x = 42
》caluculation of coins = 2.5 ×42 = 105 rupee coins (ans)
☆i hope its help☆
given by:-
》Murari has total of rs= 210
》coins type = one rupee , 50paise , 25 paise
》their ratio is = 2.5:3:4
》thirt coins = 2.5x , 3x ,4x
acourding to quetions-
change in paise
》2.5x×(100)+3x×(50)+4x×(25) = 210×100
》250x +150x+100x = 21000
》500x = 21000
》x= 21000/500
》x = 42
》caluculation of coins = 2.5 ×42 = 105 rupee coins (ans)
☆i hope its help☆
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