Question

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Answer 1

${m}^{ - 2} {n}^{6} \times {m}^{3} {n}^{ - 8} \\ = {m}^{1} {n}^{ - 2} \\ = \frac{m}{ {n}^{2} }$

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Answer 2

Answer:

M-2 n6 x m3 n-8

= m-2+3 x n6-8

= m1 n-2

= m/n^2

Step-by-step explanation:

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