Math, asked by RajNarayan198, 11 months ago

Must try.
Sweets Stall was placing an order for making cardboard boxes for packing
heir sweets. Two sizes of boxes were required. The bigger of dimensions
5 cm x 20 cm x 5 cm and the smaller of dimensions 15 cm x 12 cm x 5 cm. For all the
Carlaps, 5% of the total surface area is required extra. If the cost of the cardboard is
74 for 1000 cm’, find the cost of cardboard required for supplying 250 boxes of each
kind.​

Answers

Answered by mlbb8081
8

Step-by-step explanation:

dimensions of first box=25*20*5

total surface area of first box=2(lb+bh+hl)

=2(25×20+20×5+25×5)

=2(500+100+125)

=2×725

=1450cm^2

dimensions of second box=15×12×5

total surface area of second box=2(15×12+12×5+5×15)

=2(180+60+75)

=2(315)

=630cm^2

total surface area of both boxes=1450+630=2080cm^2

5% overlapping=5/100×2080=104cm^2

now,total surface area with overlapping=2080+104=2184cm^2

cost of cardboard for 1000cm^2=4

cost of cardboard for 1cm^2=74//1000

cost of cardboard for 2184cm^2=74/1000×2184

cost for 250 such boxes=4/1000×2184×250=rs.2184

MARK BRAINLIEST PLZ

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