Biology, asked by Anonymous, 8 months ago

Mutations in the genome of E. coli are introduced at a rate of 1/10^9 bp per generation. If a scientist starts with a colony of 10^6 cells having 1000 bp DNA, the number of mutant cells observed after two doubling times will be:

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Answers

Answered by Madhavan2001
1

Answer:

With ≈3×109 bp in the human genome the mutation rate leads to about 10-8 mutations/bp/generation x 3×109 bp/genome ≈ 10-100 mutations per genome per generation (BNID 110293). Using an order of magnitude of 100 replications per generation, we arrive at 0.1-1 mutations per genome per replication.

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