Question

mutiply -8/27xyz (3/2xyz^2-9/4xy^2z^3)​

Answer 1

Step-by-step explanation:

$\frac{8}{27} xyz ( \frac{3}{2} xyz^2- \frac{9}{4} xy^2z^3) \\ = \frac{4}{9} x {}^{2} y {}^{2} z^3- \frac{2}{3} x {}^{2} y^3z^4$