Question

Mutiply:-

$( \dfrac{1}{3} x - {y}^{ \dfrac{2}{5} }) ( \dfrac{1}{3}x + {y}^{ \dfrac{2}{5} } )$

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Answer 1

Step-by-step explanation:

given=>

$( \dfrac{1}{3} x - {y}^{ \dfrac{2}{5} }) ( \dfrac{1}{3}x + {y}^{ \dfrac{2}{5} } )$

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to find=>

$( \dfrac{1}{3} x - {y}^{ \dfrac{2}{5} }) ( \dfrac{1}{3}x + {y}^{ \dfrac{2}{5} } )$

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solution=>

=$( \dfrac{1}{3} x - {y}^{ \dfrac{2}{5} }) ( \dfrac{1}{3}x + {y}^{ \dfrac{2}{5} } )$

$= ( \frac{1}{3}x - y {}^{ \frac{2}{5} } )( \frac{1}{3}x + y {}^{ \frac{2}{5} } ) \\ \\ = ( \frac{1}{3}x ) {}^{2} - (y {}^{ \frac{2}{5} } ) {}^{2} \\ \\ = \frac{1}{9} x {}^{2} - y {}^{ \frac{2}{5} \times 2} \\ \\ = \frac{1}{9}x {}^{2} - y {}^{ \frac{4}{5} }$

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answer=>

$\\ = \frac{1}{9} x {}^{2} - y {}^{ \frac{4}{5} }$

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formula uses=>

$= >( a + b)(a - b) = a {}^{2} - b {}^{2} </h3><h3> \\ \\ =>( a {}^{m)} {}^{n} = a {}^{m \times n}$

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I hope it helps you❤

Answer 2

Answer:

$=( \dfrac{1}{3} x - {y}^{ \dfrac{2}{5} }) ( \dfrac{1}{3}x + {y}^{ \dfrac{2}{5} } )(31x−y52)(31x+y52)</h3><h3>\begin{gathered} = ( \frac{1}{3}x - y {}^{ \frac{2}{5} } )( \frac{1}{3}x + y {}^{ \frac{2}{5} } ) \\ \\ = ( \frac{1}{3}x ) {}^{2} - (y {}^{ \frac{2}{5} } ) {}^{2} \\ \\ = \frac{1}{9} x {}^{2} - y {}^{ \frac{2}{5} \times 2} \\ \\ = \frac{1}{9}x {}^{2} - y {}^{ \frac{4}{5} } \end{gathered}=(31x−y52)(31x+y52)=(31x)2−(y52)2=91x2−y52×2=91x2−y54</h3><h3></h3><h3>$

Step-by-step explanation:

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