Question

Mv/t=ma dimensionally correct or incorrect

Answer 1

Explanation:

$\sf Required\:Answer\begin{cases}\bf {Correct\:Question:-} \\ \sf {{\dfrac {m (v-u)}{t}}=ma} \\ \bf {LHS:-} \\ \sf {According\:to\:laws\:of\:kinematics} \\ \sf {F={\dfrac {m (v-u)}{t}}} \\ \bf {RHS:-} \\ \sf{According\:to\:Eizak\:Newton} \\ \sf {F=ma} \\ \sf {Now\:compare \:LHS\:and\:RHS} \\ \sf {{\dfrac {m (v-u)}{t}}=ma} \\ \implies\sf {F=F} \\ \therefore \sf {LHS=RHS {}_{(proved)}} \\ \sf {Hence\:it's\:correct}\end {cases}$