mx+ny=m^2-n^2 and ny+mx=0 find the value of x+y
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Answered by
1
ny + mx = 0
so
m^2 - n^2 = 0 ( mx+ny = m^2 -n^2)
m^2 = n^2
m = n
mx + ny =0
nx + ny = 0
n (x+y) =0
x+y=0
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so
m^2 - n^2 = 0 ( mx+ny = m^2 -n^2)
m^2 = n^2
m = n
mx + ny =0
nx + ny = 0
n (x+y) =0
x+y=0
PLEASE SELECT MY ANSWERS AS BRAINLIEST
Answered by
1
sorry to say,but i think this question is wrong. because at the same time you can't have two different value for same variable.
like mx+ny=m^2-n^2. and ny+mx=0
like mx+ny=m^2-n^2. and ny+mx=0
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