Question

mx+ny=m^2+n^2
x+y=2m​

Answer 1

Given

mx-ny=m^2+n^2-------(1)

x+y=2m--------(2)

multiplying eq(1) by coefficient of x i.e.1 and eq(2) by coefficient of x i.e. m

we get,

mx-ny=m^2+n^2-------(3)

mx+my=2m^2----------(4)

subtracting eq(3) and (4) we get

-y(m+n)=m^2+n^2-2m^2

or -y(m+n)=-m^2+n^2

              =-(m+n)(m-n)/(m+n)

             y = m-n-----(5)

by putting the value of y in eq.(2) we get,

x=2m-(m-n)

hence solution is , x=m+n &y=m-n