mx - ny = m^2 + n^2
x + y = 2m
by substitution method
Answers
Answered by
6
Answer value of x is (m + n) and value of y is (m - n)
Step-by-step explanation:
SOLUTION
Given,
mx - ny = m² + n²
x + y = 2m
Find,
the value of x and y.
SO,
mx - ny = m² + n²
mx = m² + n² + ny
x = m² + n² + ny/m
Let x be (m² + n² + ny/m)
x + y = 2m
=> (m² + n² + xy/m) + y = 2m
=> m² + n² + xy + ym/m = 2m
=> m² + n² + y(m + n) = 2m²
=> y(m + n) = 2m² - m² - n²
=> y(m + n) = m² - n²
=> y(m + n) = (m - n)(m + n)
=> y = (m -n)(m + n)/m + n
=> y = m - n
x = m² + n² + xy/m
=> x = m² + n² + x(m -n)/m
=> x = m² +.n² + mn -n²/m
=> x = m² + mn/m
=> x = m(m + n)/m
=> x = m + n
Hence,
the value of x is (m + n) and value of y is (m - n)
Answered by
3
Step-by-step explanation:
mx - ny = m^2 + n^2
x + y = 2m
by substitution method
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