Question

MY AGE IS FOUR TIMES THE DIFFERENCE OF MY AGE AFTER FOUR YEARS ANDMY AGE THREE YEARS BACK.HOW OLD AM I

Answer 1

age after 4 yrs= (x+4)
age before 3 yrs= (x-3)
difference= (x+4) - (x-3) = x+4-x+3 = 7
age=4×7=28 yrs

Answer 2

Answer:

28 years

Step-by-step explanation:

Let my present age be x

After 4 years, my age was x+4

3 years ago, my age was x-3

Now we are given that my age is four times the difference of my age after 4 years and before 3 years back

So, $x = 4(x+4-(x-3))$

$x = 4(x+4-x+3)$

$x = 4(7)$

$x = 28$

Hence my age is 28 years