Question

My ALU can perform 63 operations and there are 5 registers in my datapath. Write
the respective machine code which should be generated by Controller for the
following Micro-Instructions:
MDR1
BUSIN
(Use the order of registers as follows: IR, MAR, MDR1, MDR2, PC MUXI, MUXU, MUX2
(ALU))
Let us assume that code of ALU for memory instruction is 000000 and O for Muxi to pick
data from MDR2 and 1 for MUX1 to pick data from PC. Lets o for
me to pak data from
DataBus and 1 from ALU.​

Answer 1

Answer:

sorry but I don't know what is this subject

Explanation:

sorry but I don't know what is this subject

Answer 2

Answer:

The programming respective machine code should be generated by the Controller for the following Micro-Instructions

Explanation:

Multiplication of two 8 bits numbers using 8085 microprocessor with carry.

Algorithm:

1. Load HL pair with initial data using LHLD command.
2. Exchange the data of HL and DE pair using XCHG command.
3. Copy the data of register D into Register C.
4. Now initialize register D with 0.
5. Also initialize HL pair with 0 using LXI command.
6. Use the DAD command to add the data of DE pair into the data of HL pair and store in HL Pair.
7. Decrease the value of C by one.
8. Check if the result from previous instruction resets the zero flag and if true, jump to address XXX.
9. Store the content of the HL pair into desired location.
10. Stop.

Program:

LHLD 2050

XCHG  

MOV C, D

MVI D 00

LXI H 0000

xxx DAD D  

DCR C  

JNZ 200A

SHLD 3050

HLT

Observation:

   INPUT:

   2050:43

   2051:07

   OUTPUT:

   3050:D5

   3051:01

Algorithm

1. Start the program by loading HL register pair with address of memory location.

2. Move the data to a B register.

3. Get the second data and load into Accumulator.

4. Add the two register contents.

5. Check for carry.

6. Increment the value of carry.

7. Check whether repeated addition is over and store the value of product and carry in memory location.

8. Terminate the program.

Program and Result

 

         MVI D, 00       ;Initialize register D to 00

         MVI A, 00       ;Accumulator content to 00

         LXI H, 5000

         MOV B, M        ;Get the first number in B - reg

         INX H           ;Increment HL pair of register

LOOP: ADD B               ;Add content of A - reg to register B

         MOV C, M        ;Get the second number in C- reg

         JNC             ;NEXT Jump on no carry to NEXT.

         INR  D          ;Increment content of register D

NEXT: DCR C               ;Decrement content of register C

         JNZ LOOP        ;Jump on no zero to address

         STA 5002        ;Store the LSB of result in Memory

         MOV A, D        ;Move content of D-Reg to A-Reg

         STA 5003        ;Store the MSB of result in Memory

         HLT             ;Terminate the program.

Result:

Input:

Data 1: 80H in memory location 5000

Data 2: 76H in memory location 5001

Output:

Data 1: 00H in memory location 5002

Data 2: 0AH in memory location 5003