Question

my answer should be like this( as I send a pic) and ur questin is
how much of heat energy is required when 20grams of ice at 0°c to convert water vapour at 100°c ??
if u say correct i will send u 200 points
if ur like icant idont know
i will report that​

Answer 1

Answer:

2000 cal , 8360 J.

mass of water = 20 gm

Change in temperature = 100-0 = 100

Heat energy required = mass of water (gm)× Change in temperature (°C) cal.

heat  = mass * change in temperaure

= 20 × 100 = 2000 cal

1 Joule= 4.18  * 1cal

=2000 × 4.18 = 8360 J

Explanation:

PLZZ MARK ME AS BRAINLIEST ANSWER AND SEND 200 POINTS AS U SAID

Answer 2

Answer:

$\huge\underline\bold\red{♡AnsWeR♡}$