Question

my answer the questions​

Answer 1

$\sf{1) \: Given :-}$

$\sf{Current \: I = 2 \: A}$

$\sf{Time \: t = 3 \: s}$

$\sf{Potential \: Difference \: V = 6 \: V}$

$\sf{From \: relation, }$

$\sf{Current \: I \: = \: \frac{ Charge \: q } {Time \: t }}$

$\sf{Charge \: q \: = \: Current \: I \times Time \: t}$

$\sf{q \: = \: 2 \times 3 \: C}$

$\sf{ q \: = \: 6 \: C}$

$\sf{From \: relation, }$

$\sf{Potential \: Difference \: V = \frac{Work \: Done \: W}{Charge \: q}}$

$\sf{Work \: Done \: W = Potential \: Difference \: V \times Charge \: q}$

$\sf{W \: = 6 \times 6 \:J}$

$\sf{W \: = 36 \:J}$

$\sf{2) \: Given :-}$

$\sf{Total \: Electrons \: Drawn \: n= 2 \times {10}^{20} electrons}$

$\sf{Charge \: of \: 1 \: electron \: e= 1.6 \times {10}^{ - 19} \: C}$

$\sf{Time \: t = 2 \: min = 120 \: s }$

$\sf{Total \: Charge \: Passed \: Q = n \times e}$

$\sf{Q = (2 \times {10}^{20}) \times (1.6 \times {10}^{-19})}$

$\sf{Q = 32 \: C}$

$\sf{Current \: I = \frac{Charge \: Q}{Time \: t}}$

$\sf{I = \frac{32}{120} \: A}$

$\sf{I = 0.26\: A}$

$\sf{3) \: Given :-}$

$\sf{Current \: I = 5 \: A}$

$\sf{Time \: t = 1 \: min = 60 \: s}$

$\sf{Potential \: Difference \: V = 1 \: V}$

$\sf{Charge \: Q = Current \: I \times Time \: t}$

$\sf{Q = 5 \times 60 \:C}$

$\sf{Q = 300\:C}$

$\sf{Work \: Done \: W = Potential \: Difference \: V \times Charge \: Q}$

$\sf{W = 1 \times 300 \:J}$

$\sf{W = 300 \:J}$

$\sf{In \: Question \: Number \: 2 \: and \: 3 \: The \: Potential \: Difference \: is \: not \: visible.}$