Question

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Find the lateral curved surface area of a cylindrical petrol storage tank that is 4.2
m in diameter and 4,5 m high, How much steel was actually used, if of steel
actually used was wasted in making the closed tank?​

Answer 1

Answer:

R=2.1

R=2.1h=4.5

R=2.1h=4.5lateral surface area=2 pi r h

R=2.1h=4.5lateral surface area=2 pi r h=2*22/7*2.1*4.5=59.4

R=2.1h=4.5lateral surface area=2 pi r h=2*22/7*2.1*4.5=59.4total stell used= total surface area

R=2.1h=4.5lateral surface area=2 pi r h=2*22/7*2.1*4.5=59.4total stell used= total surface area=59.4*2*22/7*2.1*2.1=1646.56m^2

R=2.1h=4.5lateral surface area=2 pi r h=2*22/7*2.1*4.5=59.4total stell used= total surface area=59.4*2*22/7*2.1*2.1=1646.56m^2metal was used

R=2.1h=4.5lateral surface area=2 pi r h=2*22/7*2.1*4.5=59.4total stell used= total surface area=59.4*2*22/7*2.1*2.1=1646.56m^2metal was usedto find actually steel used u can find 1/12 of this

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Answer 2

Answer:

R=2.1

R=2.1h=4.5

1

5.0

R=2.1h=4.5lateral surface area=2 pirh

R=2.1h=4.5lateral surface area=2 pir

h=2*22/7*2.1*4.5=59.4

R=2.1h=4.5lateral surface area=2 pir h=2*22/7*2.1*4.5=59.4total stell used= total surface area

R=2.1h=4.5lateral surface area=2 pi r h=2*22/7*2.1*4.5=59.4total stell used= total surface area=59.4*2*22/7*2.1*2.1=1646.56m^2

R=2.1h=4.5lateral surface area=2 pi r h=2*22/7*2.1*4.5=59.4total stell

used= total surface area=59.4*2*2

2/7*2.1*2.1=1646.56m^2metal was

used

R=2.1h=4.5lateral surface area=2 pir h=2*22/7*2.1*4.5=59.4 total steel used= total surface area=59.4*2*22/7*2.1*2.

1=1646.56m^2metal was usedto find actually steel used u can find 1/12 of this

hope it helps you