my dear friends please answer only 6 questions.
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I Can Give the Way to Solve :
Step-by-step explanation:
Given, ∠POQ=130°
We know,
∠OPT=∠OQT=90°
(Angle between the tangent and the radial line at the point of intersection of the tangent at the circle)
Now, in quadrilateral POQT
Sum of angles=360
∠OPT+∠OQT+∠PTQ+∠POQ=360°
90+90+∠PTQ+130=360
∠PTQ=360−310
∠PTQ=50°
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