my father age 5 years ago plus twice my age now gives 65 . My age 5 years ago plus three times my father age now gives 130 . what is my father age?
Answers
Answer:
Answer
Let the ages of father and his son be x and y respectively.
Case I:- The sum of the ages of father and his son is 65 years.
age of father + age of son = 65
⇒x+y=65⟶(i)
Case II:- After 5 years, fathers age will be twice the age of his son.
Age of father = 2 (age of son)
⇒x+5=2(y+5)
⇒x+5=2y+10
⇒x=2y+5⟶(ii)
From eq
n
(i)&(ii), we have
(2y+5)+y=65
⇒3y=65−5
⇒y=20
Substituting the value of y in eq
n
(i), we have
x+20=65
⇒x=45
Hence, the present age of father and son is 45 and 20 respectively and equation (i)&(ii) are the pair of linear equations in two variables.
Answer:
your father's age is 40 years
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Step-by-step explanation:
Let father's present age be x and your present age be y
Father's age five years ago= x-5
your age five years ago= y-5
Case 1, (x-5) + 2y= 65
x + 2y= 70 (eqn. 1)
Case 2, y - 5 + 3x = 130
3x + y= 135 (eqn. 2)
Eqn 1 is x+2y=65
y= 65/2 - x/2 (eqn 3)
Putting 3 in 2
3x + 65/2 - x/2= 135
6x/2 - x/2 +65/2 =135
5x/2 + 65/2= 135
5x + 65 = 135 × 2
5x= 270-65=205
x= 41
Putting the value of x in eqn 3
y= 65/2-41/2
y=24/2
y=12
(This part was not asked in the question)
Ans- Father's present age is 41
