MY FATHER'S AGE 5 YEARS AGO PLUS TWICE MY AGE NOW GIVES 65. MY AGE 5 YEARS AGO PLUS THREE TIMES MY FATHER'S AGE NOW GIVES 130. WHAT IS MY FATHER'S AGE?
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Answered by
11
Answer:
hey here is your answer
pls mark it as brainliest
so here we go
Step-by-step explanation:
let age of my father be x years and that of mine be y years
so according to first condition
(x-5)+2y=65
ie x+2y=70 (1)
according to second condition
(y-5)+3x=130
ie 3x+y=135 (2)
multiply (2) by 2
we get
6x+2y=270 (3)
so subtract (1) from (3)
we get
5x=200
ie x=40
hence age of my father currently is 40 years
Answered by
3
let age of my father be x years and that of mine be y years
so according to first condition
(x-5)+2y=65
ie x+2y=70 (1)
according to second condition
(y-5)+3x=130
ie 3x+y=135 (2)
multiply (2) by 2
we get
6x+2y=270 (3)
so subtract (1) from (3)
we get
5x=200
ie x=40
hence age of my father currently is 40 years
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