My father's age 5 years plus
twice my age now gives 65.
My age 5 years ago plus three times my father's age now gives 130 .What is my father's age?
Answers
Answered by
1
Answer:
The present age of father and son is 45 and 20 respectively.
Step-by-step explanation:
Let the ages of father and his son be x and y respectively.
Case I:- The sum of the ages of father and his son is 65 years.
age of father + age of son = 65
⇒x+y=65⟶(i)
Case II:- After 5 years, fathers age will be twice the age of his son.
Age of father = 2 (age of son)
⇒x+5=2(y+5)
⇒x+5=2y+10
⇒x=2y+5⟶(ii)
From eq
n
(i)&(ii), we have
(2y+5)+y=65
⇒3y=65−5
⇒y=20
Substituting the value of y in eq
n
(i), we have
x+20=65
⇒x=45
Answered by
0
Answer:
41
Step-by-step explanation:
this happens when his fathers present age is y
his present age is x
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