Question

my friend rita hasbought 5 pens and 3 pencils at rs.34fromthebook-shop nearby our school .but sumita has bought 7 pens and 6 pencil at rs.53 at the same rate and from the same shop. i write by calculating the price of each pen and pencil by framing simultanaeous equations.​

Answer 1

Answer:

Step-by-step explanation:

let the value of pens be x and pencils be y

then,

A/q

5x+3y=rs34. eq 1

7x+6y=rs 53. eq 2

multiplying eq 1 with2 we have

10x+6y=68 eq 3....

now subtracting eq 3with 2 we have...

10x+6y=68

7x+6y=53

3x=15

x=5

now finding value of y

putting value of x in eq 2

7*5+6y=53

35+6y =53

6y=18

y=3

Answer 2

Answer: Cost of each pen is 5 rupees and that for a pencil is 3 rupees

Step-by-step explanation:

Let the cost of each pen be x and the cost of pencil be y

According to the question,

5x+3y=34 --1

7x+6y=53 --2

These are the 2 simultaneous equations

Now, let us solve these two equations using elimination method.

Multiplying equation 1 by two, we get

10x+6y=68 --3

Subtracting equation 2 from equation 3, we get

3x=15

x=15/3=5

x=5

Now, you can substitute the value of x in equation 1 to get

5*5+3y=34

25+3y=34

3y=34-25

3y= 9

y=9/3= 3

Therefore, cost of a pen is 5 rupees

Cost of a pencil is 3 rupees