Math, asked by alinawang888, 1 year ago

My friend sets out walking at a speed of 3 miles per hour. I set out behind her 5 minutes later at 4 miles per hour.

For how many minutes will my friend have been walking when I catch up to her?

Answers

Answered by naysahsheikh5
0

Answer

Step-by-step explanation:

When you catch up with your friend, your friend and you would have walked the same distance. But you would cover the same distance in 5 minutes less as you started later.

So, Speed= distance/ time

Therefore, Distance= Speed × Time

Let the time taken be x hrs.

Using the above relation,

4 {x-(5/60)} = 3x

4x- 1/3 = 3x

x = 1/3 hrs.

Or x = (1/3) × 60 = 20 minutes.

Therefore, you and your friend will meet in 20 minutes.

Answered by monikasaha661
0

Answer:Step-by-step explanation:

When you catch up with your friend, your friend and you would have walked the same distance. But you would cover the same distance in 5 minutes less as you started later.

So, Speed= distance/ time

Therefore, Distance= Speed × Time

Let the time taken be x hrs.

Using the above relation,

4 {x-(5/60)} = 3x

4x- 1/3 = 3x

x = 1/3 hrs.

Or x = (1/3) × 60 = 20 minutes.

Therefore, you and your friend will meet in 20 minutes.

Read more on Brainly.in - https://brainly.in/question/15197453#readmore

Step-by-step explanation:

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