Question

.My mother is 12 years more than twice my age. After 8 years, my mother's age will be 20 years less than three times my age. Find my age and my mother's age. ​

Answer 1

Answer:

My age : 16, mothers age : 44 years

Step-by-step explanation:

Let my age be x

my mothers age : 2x+12

After 8 years

my age : x+8

mothers age : 2x+20 {1}

or ATQ

3(x+8)-20 -- {2}

Equating 1 and 2 we get,

2x+20=3x+4

x=16

my age = 16 years

mothers age = 44 years

Answer 2

Answer:

hence son's age=16 yrs

and mothers age=44 yrs

Step-by-step explanation:

Let my present age of her son be x

My mother is 12 years more than twice my age

So, Mother's present age = 2x + 12

After 8 years

Mother's age =  2x + 12 +8 = 2x + 20

My Age will be x+8

Now we are given that my mother's age will be 20 years less than three times of my age.

2x + 20 = 3(x + 8) - 20

2x + 20 + 20 = 3(x + 8)

2x + 40 = 3x + 24

2x - 3x = 24 - 40

-x = -16

x = 16

hence son's age=16 yrs

and mothers age=44 yrs