Question

My mother’s age is 4 times my age. After 10 years, my mother’s age will be 6 years more than two times my age. Find my age and my mother’s age​

Answer 1

My present age is 16 years and my mother's present age is 44 years.

Step-by-step explanation:

Let my present age be x

Now we are given that My mother is 12 year more than twice my age.

So, Mother's present age =

After 8 years

Mother's age =

My Age will be x+8

Now we are given that my mother's age will be 20 years less than three times of my age.

My age = 4 years

Mother's Age =

Hence My present age is 16 years and my mother's present age is 44 years

Answer 2

Step-by-step explanation:

Let the present age of son = x

Then the present age of the mother will be = 4x.

After 16 years,

Age of son will be = x+16

Age of mother will be = 4x+16

Now,

2(x+16) = (4x+16)

Solving for x, we get x as 8.

Therefore,

Present age of son = x = 8

Present age of mother = 4x = 32