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Answer:
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question
Let numerator be x - 1
Let numerator be x - 1Denominator be x
Let numerator be x - 1Denominator be xAccording to the Question:-
Let numerator be x - 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x - 1 + 4 } { 2x } ⟹
Let numerator be x - 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x - 1 + 4 } { 2x } ⟹ 2x
Let numerator be x - 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x - 1 + 4 } { 2x } ⟹ 2xx−1+4
Let numerator be x - 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x - 1 + 4 } { 2x } ⟹ 2xx−1+4
Let numerator be x - 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x - 1 + 4 } { 2x } ⟹ 2xx−1+4
Let numerator be x - 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x - 1 + 4 } { 2x } ⟹ 2xx−1+4 \tt\implies \: x + 3 = 2x⟹x+3=2x
Let numerator be x - 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x - 1 + 4 } { 2x } ⟹ 2xx−1+4 \tt\implies \: x + 3 = 2x⟹x+3=2x\tt\implies \: 2x - x = 3⟹2x−x=3
Let numerator be x - 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x - 1 + 4 } { 2x } ⟹ 2xx−1+4 \tt\implies \: x + 3 = 2x⟹x+3=2x\tt\implies \: 2x - x = 3⟹2x−x=3\tt\implies \: x = 3⟹x=3
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