Question

'my present age if four times the difference of my age after four years and my age three years ago' .how will you represent this solution in linear equations form? also find my present age

Answer 1

Hello
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Let my present age be x years

Then, My age after four years = (x + 4) years

My age three years ago = (x - 3) years

Now,
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According to the question,

x = 4 × [ (x + 4) - (x - 3) ]

=> x = 4 × (x + 4 - x + 3)

=> x = 4 × 7

=> x = 28 years

Therefore ,
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My present age = x years = 28 years

HOPE IT HELPS

Answer 2

let x is the present age

x=4[x+4-(x-3)]

x=4[x+4-x+3]

x=4[7]

x=28