Question

My present age is four times the difference of my age after four years
and my age three years ago."
1. How will you represent this situation in linear equation form?
2. What is my present age in years?​

Answer 1

Answer:

plz give me thanks

Step-by-step explanation:

hope it helped u

Answer 2

$\huge† \huge \bold{\: \pmb {\red{ Answer }} }$

Let my present age be x years

Then, My age after four years= (x + 4) years

My age three years ago = (x - 3) years

Now,

According to the question,

$\sf \: x = 4 x [(x + 4) - (x-3) ] \\ \\\sf \implies \: x = 4 x (x + 4x + 3) \\ \\ \sf \implies \: x = 4 × 7 \\ \\\sf \implies \red{ x = 28 \: years}$

Therefore,

My present age = x years = 28 years