Question

my queation is
3^x+3^(-x)=2
can someone please tell me the solution​

Answer 1

Step-by-step explanation:

hope you understand the steps

Answer 2

Answer:

Step-by-step explanation:

3^x+3^-x=2

$3^x+1/3^x=2$

(3^2x + 1)/3^x=2

Let 3^x=t

$\frac{t^2+1}{t} =2\\t^2+1=2t\\t^2-2t+1=0\\(t-1)^2=0\\t-1=0\\t=1\\\\ 3^x=1\\3^x=3^0\\\\Therefore, x=0$

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