Question

My Question-
If my number is-68,423

Test the divisibility of the number chosen by 3, 4, 5, 6, 7, 8 and 9 (Explanation should be given)

Answer 1

Answer:

68423 divisibility by 2 - at the ones digit there should be 2 4 6 8 or 0, So in the given number at once digit there is 3, the number is not divisible by 2.(It is not given in the question.)

68423 divisibility by 3 - the sum of all digits should be divisible by 3, so in the given number the sum of all digits is 6+8+4+2+3=23, 23 is not divisible by 3. So the number is not divisible by 3.

68423 divisibility by 4 - the last two digits of a number should be divisible by 4,23 is not divisible by 4, So the number is not divisible by 4.

68423 divisibility by 5- the last digit should be 0 or 5., So in the given number the last digit is 3, the number is not divisible by 5.

68423 divisibility by 6 - the number should be divisible by both 2 and 3 then only it will be divisible by 6, the given number is not divisible by both 2 and 3 and it is also so not divisible by 6.

68423 divisibility by 7- multiply the last digit by 2 and then subtract the product by the remaining numbers, in the given number 3 would be multiplied by 2 and subtracted by the remaining numbers like this 6842-6=6836, and then repeat it until it comes in two digit. 683-12=671 ; 67-2=65; and then check it wheather it is divisible or not. 65 is not divisible by 7, so the number is not divisible by 7.

68423 divisibility by 8- last three digits should be divisible by 8,then the number would be divisible by 8. 423 is not divisible by 8,so the number is not divisible by 8.

68423 divisibility by 9- sum of all digits should be divisible by 9, so in the given number sum of all the digits is 6+8+4+2+3=23, 23 is not divisible by 9, so the number is not divisible by 9.

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Answer 2

Answer:

divisibility by 3 : no ,as the sum of the number is not divisible by 3

divisibility by 4 : no, as the last to digits are not divisible by 4

divisibility by 5: no, as the the last digit is not 5 or 0

divisibility by 6: no, as the number is not divisible by 3 and 2

divisibility by 7: no, as after taking the last digit of the number and doubling it and subtracting it with the rest of the number didn't turn out to be divisible by 7

divisibility by 8: no, as the the last 3 digits are not divisible by 8

divisibility by 9: no, as the sum of the number is not divisible by 9