History, asked by ritakaur20, 1 year ago

my question is....✌✌✌✌✌♠️♠️♠️

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Answered by Anonymous
4

HOLA MATE..!!

ANSWER:-

t = 0

y= 1 / 1 + x^2  

or 1 + x^2 = 1/ y

x^2 = 1/y -1 = ( 1 -y ) / y

x = (1/y /y) ^ 1/2

now t = 2 , we have

or y = 1 / [1 + (x -1)^2 ]

(x - 1)^2 = 1/y = 1 - y/ y

x = 1 + {[ 1 - y]/ y}^1/2

1/2 = x^2 - x / t ^2 - t

now,

[ 1 + [ 1 - y /y ]^ 1/2  - [1/ y / y ] ^ 1/2 ] / 2 - 0

= 1/2 - 0 = 0.5 ms

hope it helps..!1

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