Question

My question is. Find the largest number of 2 digit which is a perfect square.

Answer 1

Answer,
Let us take the first 3 digit number,

First 3 digit number = 100

Now,

We know that,

100 is a perfect square.

And,

Its square root is 10.
Now,

The number before 10 is 9.

Square of 9 = 81

Hence,
The largest 2-digit number which is a perfect square is 81.

Thanks!!

Answer 2

the largest two digit no. os 81 =9^2 as 10^2 =100
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