Math, asked by shreyaupsc08, 3 days ago

My question is for the 9th one​

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Answered by krupa212010106
1

Circumference of the circle= 2πr

→22= 2πr

→22= 2×\frac{22}{7}×  r

→ 11= \frac{22}{7}× r

→ r= \frac{7}{2}

Area of quadrant= \frac{1}{4} πr^{2}

= \frac{1}{4}×\frac{22}{7}×\frac{7}{2}×\frac{7}{2}

= 9.625cm^{2}

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