Question

my question is:
if we handsack with 100 person together then how many times the handsack is done....
don't say that the answer is 100 this will be wrong....
wrong answer will deleted.​

Answer 1

Answer:

$\blue{\bold{\underline{\underline{\boxed{answer :4950 \: handshakes }}}}} \:$

$hey \: buddy \: \\ \\ here \: is \: your \: answer \: \\ \\ when \: one \: person \: handshake \: with \: other \\ then \: no.of \: handshake \: is \: one. \\ therefore \: when \: all \: people \: handshake \: with \\ \: eachother \: then \\ no.of \: handshakes = \frac{n(n + 1)}{2} \\ \: \: \: \: \: = \frac{99(99 + 1)}{2} = \frac{9900}{2} = 4950 \\ \\ therefore \: 4950 \: handshakes \: is \:the \: answer.$

pls mark it as brainliest

Answer 2

Step-by-step explanation:

1st person=9 Shake hands

Then the second person will shake hands with 8 other persons because he had already shaken hand with the first person.

2nd person=8 Shake hands(1 Shakehand already done with the first person)

Similarly,3rd person will shake hand with 7 other persons….And This series will go on…

i.e. 3rd person=7 Shake hands,4th person=6 Shake hands…and so on….

Thus,total number of shake hands=9+8+7+6+5+4+3+2+1=45 Shake Hands

Alternatively,

Using formula,

n(n-1)/2

Where, ”n” is number of persons.

That is ,when 10 person shake hands with 9 others . No of Combinations are 10*(10–1)=90

But if one person shake hand with the other there will be no vice versa combination…

For Example,if a shake hand with b ,b would not again shake hand with a…

Thus ,we have to divide the total combinations by 2 in order to avoid repeatitive combination…

Thus, 90/2=45

45 Shake hands