Question

my question is no. is 3

Answer 1

Answer:

Step-by-step explanation:

Question-3 :-  The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4 2⁄15 cm . What is the length of either of the remaining equal sides?

Solution :-  

 Let each of equal sides of an isosceles triangle = x cm.  

 The base of an isosceles triangle = 4/3 cm

 Perimeter of a triangle = 4 2⁄15 cm

 Sum of three sides = 4 2⁄15 cm

 Accordding to question :  

 x + 4/3 + x = (60 + 2)/15

 2x = 62/15 - 4/3

 2x = (62 - 20)/15

 2x = 42/15

  x = 42/30

  x = 7/5

 Each of equal sides of an isosceles triangle = x = 7/5 cm.

Answer 2

Answer:

⇒ (7/5) cm (or) 1 2/5 cm.

Step-by-step explanation:

Let the length of the remaining equal sides be 'x'.

Given, base = (4/3) cm.

Given, Perimeter = 4 (2/15) cm.

We know that In an isosceles triangle has exactly two equal sides.

⇒ (4/3) + x + x = 4 (2/15)

⇒ (4/3) + 2x = 62/15

⇒ 2x = (62/15) - (4/3)

⇒ 2x = 42/15

⇒ x = 7/5.

Therefore, the length of equal sides is 7/5 cm (or) 1 (2/5) cm.

Hope it helps!