Question

my question is p(x) = x2 + 5x + 6​

Answer 1

$p(x) = {x}^{2} + 5x + 6$

$let \: p(x) \: = \: 0$

${x}^{2} + 5x + 6 = 0$

${x}^{2} + 2x + 3x + 6 = 0$

$x(x + 2) + 3(x + 6) = 0$

$(x + 2)(x + 3) = 0$

$x + 2 = 0 \: or \: x + 3 = 0$

$x = - 2 \: or \: x = - 3$

Answer 2

Answer:

if you asking for roots then answer is x = -2,-3

Step-by-step explanation:

${x}^{2} + 5x + 6 = 0 \\ {x}^{2} + 2x + 3x + 6 = 0 \\ x(x + 2) +3 (x + 2) = 0 \\ (x + 3)(x + 2) = 0 \\ x = - 2 \: \: - 3$