Question

my question is please give my answers

Answer 1

let 3√2 / 5 be an rational no.

then
$\frac{3 \sqrt{2} }{5} = \frac{a}{b}$
where a and b are co prime integers and b is not equal to 0

$\sqrt{2} = \frac{5a}{3b}$
Now, a and b are integers so 5a/3b is a rational no. So , RHS is rational. But we know that √2 is irrational. But this is a contradiction. So, our assumption is wrong.

Therefore, 3√2/5 is an irrational no.

Hope it helps you
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Answer 2

heya!!!!...ur ans..
please mark brainliest. .....