Question

my question is pleased give answer ​

Answer 1

10 th term = 47
a + 9d = 47
Given a = 2
2 + 9d = 47
9d = 45
d = 5

Sum of 15 terms = 15/2 (2a + 14d)
= 15/2 ( 4+ 70)
= 15/2 (74)
= 15 x 37
=555 ANS



Hope so it will help you

Answer 2

(1) Here let the first term of the a.p. be a and common difference be d. Therefore, a= 2
So, a10 = a + 9d
2+ 9d = 47....(1)
d = 45/9
d = 5.
So, s15 = 15/2( 2×2 + 14 × 5)
=15/2 (4 +70)
=15/2 × 74
=15 × 37
=555.
(2)Here the equation is
px(x-3) + 9 =0
px^2 - 3px +9=0
We know, for any equation to have equal roots,
D = 0
b ^2 - 4ac = 0 (where b= -3p, a= p and c = 9)
(-3p)^2 - 4p9 = 0
9p^2 - 36p = 0
p^2 - 4p = 0
p (p - 4) = 0
So, p= 0 or p = 4.