Math, asked by guru51, 1 year ago

my question is
eq {}^{n} \:  \\  x - y = 3 -  -  - (1) \\  \frac{x}{3}  +  \frac{y}{2} = 6  -  -  - (2)  \\

Answers

Answered by divyansh57
1
what is it l can't understand the question

guru51: this question is from linear equation in two variables.
divyansh57: sorry
guru51: do you know what's the answer of this question.
guru51: if you know the answer please comment me fast.
divyansh57: 2x + 3x=36,2(y+3)+3y=36,5y+6=36,5y=30,y=6,x=9
divyansh57: plese mark as barinliest
guru51: thank you so much bro.
guru51: you help me lot
guru51: I'm new user so I don't know how to mark as barinliest
Answered by barani79530
0

Step-by-step explanation:

Analysing the question,

Given:

Simple interest = ₹ 23940

Principal = ₹ 28500

Time period = 7 years

\begin{gathered}\\\end{gathered}

To find:

Rate of interest per annum = ?

\begin{gathered}\\\end{gathered}

Formula used:

\begin{gathered} \maltese \: \: \boxed { \bf{SI = \dfrac{PTR}{100}}} \\ \\ \end{gathered}

SI=

100

PTR

where:

SI is the Simple interest

P is the principal

T is the time period

R is the rate of interest

\begin{gathered}\\\end{gathered}

Solution:

Applying the above formula and substituting the given values,

\begin{gathered}\hookrightarrow \: \: \sf{23940 = \dfrac{28500 \times 7 \times R}{100} } \\ \\ \end{gathered}

↪23940=

100

28500×7×R

\begin{gathered} \dashrightarrow \: \: \sf{23940 = \dfrac{285 \cancel{00} \times 7 \times R}{ \cancel{100}} } \\ \\ \end{gathered}

⇢23940=

100

285

00

×7×R

\begin{gathered} \dashrightarrow \: \: \sf{285 \times 7 \times R = 23940} \\ \\ \end{gathered}

⇢285×7×R=23940

\begin{gathered} \dashrightarrow \: \: \sf{1995 \times R = 23940} \\ \\ \end{gathered}

⇢1995×R=23940

\begin{gathered} \dashrightarrow \: \: \sf{R = \dfrac{23940}{1995} } \\ \\ \end{gathered}

⇢R=

1995

23940

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