My question is: there is a Garland with white, red and yellow flowers is 54 in numbers. Red flowers are one less than twice of yellow flower, white flower is 1 more than twice of red flowers. If then yellow flower no. is 20,then find the number of white flower?
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Answer:
Step-by-step explanation:
CASE -1
Let the numbers of red flower be x
x = 20 × 2 - 1
= 40 - 1 = 39
Thus, no. of red flower is 39
CASE-2
Let the number of white flower be y
y = 2 × 39 + 1
= 78 + 1 = 79
THIS ANSWER IS NOT APPROPRIATE AS TOTAL NO. OF FLOWER IS 54.
SO I AM WRITING THE A ANOTHER ANSWER FOR THIS QUESTION
Let the no. of white flower be x
So, no. of red flower is = 2x - 1
So, no of white flower is = 2(2x-1) + 1 = 4x -1
NOW,
x + 2x -1 + 4x -1 = 54
⇒ 7x - 2 = 54
⇒ 7x = 54 + 2 = 56
⇒ x = 56/7 = 8
Thus , no. of yellow flower = 8
no. of red flower = 16 - 1 = 15
no. of white flower = 4 × 8 + 1 = 32 +1 = 33
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