My question is xsquareplus 3x-10
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Step-by-step explanation:
Given that : x^2+3x-10
=>x^2+2x-5x-10
=>x(x+2)-5(x+2)
=>(x+2)(x-5)
therefore,x^2+3x-10=(x+2)(x-5)
and zeroes are x+2=0=>x=-2 and x-5=0=>x=5
zeroes are 5 and -2
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